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, we can conclude much more about this class of zeta constants. Rein particular, since π displaystyle pi

Let x Beryllium a Ohne scheiß number with 0 < x < π/2, and let stickstoff be a positive odd integer. Then from de Moivre's formula and the definition of the cotangent function, we have

which hinein ur situation equates to the limiting recurrence relation (or generating function convolution, or product) expanded as

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The solution to this Harte nuss can be used to estimate the probability that two large random numbers are relatively prime.

By Vieta's formulas we can calculate the sum of the roots directly by examining the first two coefficients of the polynomial, and this comparison shows that

Why is pi here? And why is it squared? A geometric answer to the Basel Harte nuss on YouTube (animated proof based on the above)

Using the Weierstrass factorization theorem, it can also be shown that the right-hand side is the product of linear factors given by its roots, just as we do for finite polynomials (which Euler assumed as a heuristic for expanding an infinite degree polynomial rein terms of its roots, but hinein fact is not always true for general P ( x ) displaystyle P(x)

Then by applying Parseval's identity as we did for the first case above along with the linearity of the inner product yields that

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Other notably special identities and representations of this constant appear rein the sections below. Series representations[edit]

The Riemann zeta function ζ(s) is one of the most significant functions hinein mathematics because of its relationship to the Verteilung of the prime numbers. The zeta function is defined for any complex number s with Ehrlich parte greater than 1 by the following formula:

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is detailed rein expository fashion most notably in Havil's Gamma book which details many zeta function and logarithm-related series and integrals, as well as a historical perspective, related to the Euler gamma constant.[7] Generalizations of Euler's method using elementary symmetric polynomials[edit]

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